Eddie is a plant manager at North Salem Construction Company. He has been employed there for 20 years and will be retiring at the end of this year. His pension is calculated on the average of his last four years' salaries. In those years, he earned $82,000, $96,000, $105,000, snf $109,000. His employer will give him 1.2% of that average for each year he worked. Calculate Eddie's pension. *

Using the mean concept, it is found that Eddie's pension is of $23,520.

The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.

In this problem, there are 4 observations, which are $82,000, $96,000, $105,000, and $109,000, hence, the mean is:

1.2% of the average is given by:

He worked for 20 years, hence, the pension is of:

A similar problem is given at link

$23,520

Step-by-step explanation:

Given the question :

Eddie is a plant manager at North Salem Construction Company. He has been employed there for 20 years and will be retiring at the end of this year. His pension is calculated on the average of his last four years' salaries. In those years, he earned $82,000, $96,000, $105,000, snf $109,000. His employer will give him 1.2% of that average for each year he worked. Calculate Eddie's pension

Pension is calculated on the average of his last four years salary :

Salary for last four years :

82,000 + 96,000 + 105,000 + 109,000 = $392,000

Average salary over the last four years :

392,000 / 4 = $98,000

Number of years worked = 20 years

1.2% of his average salary over the last four years :

0.012 × $98,000 = $1,176

$1,176 × number of years worked

$1,176 × 20 = $23,520

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right