What is the equation of the line that has a slope of 3 and passes through the point (1, -2)? y = 3x + 5
y = 3x − 5
y = 3x + 1
None of these choices are correct.

Hey there! I'm happy to help!

All of these answer options are in slope intercept form (y=mx+b) where m is the slope and b is the y-intercept.

If our slope is 3, our m will be 3 in the equation, which matches our answer options.

We now want to find the y-intercept (b). To do this, we plug in the point (1,-2) into the equation with our slope of 3 and then solve for b.

-2=3(1)+b

We flip the equation so b is on the left.

3(1)+b=-2

3+b=-2

We subtract 3 from both sides.

b=-5

So, the equation of this line is y=3x-5.

Have a wonderful day! :D

y = 3x-5

Step-by-step explanation:

The slope intercept form of an equation is

y = mx+b  where m is the slope and b is the y intercept

y = 3x +b

Substitute the point into the equation

-2 = 3(1)+b

-2 = 3+b

Subtract 3 from each side

-5 = b

y = 3x-5

idk

step-by-step explanation:

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is