If d (x) = 2 x + 1, find d(-3) =

d(-3) = -5

Step-by-step explanation:

To find d(-3), plug in -3 wherever there is an x in d(x).

d(x) = 2x + 1

d(-3) = 2(-3) + 1

d(-3) = -6 + 1

d(-3) = -5

d(-3) = -5

Step-by-step explanation:

To find the answer substitute x for -3

This means the equation will now look like

d(-3) = 2(-3) + 1

d(-3) = -6 + 1

d(-3) = -5

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

use formula for the circle a=3.14

step-by-step explanation: