need help and friends but can you figure this out Find the equation of the tangent at ( 0 , 2) to the circle with equation (x + 2)2 + (y + 1)2 = 13 can someone be my friend:( too

2x + 3y = 6

Step-by-step explanation:

(x + 2)^2 + (y + 1)^2 = 13

Center is at (-2, -1) the slope of the radius from the center to point (0, 2) is:

slope = (2 -(-1)/(0 -(-2) = 3/2

the radius is perpendicular to the tangent line at the point of tangency and the slopes of the perpendicular lines are negative reciprocal so:

slope of the tangent line = -2/3

the equation of tangent at (0, 2) is:

y - 2 = -2/3(x - 0)

y = (-2/3)x + 2 => answer in slope - intercept form

3y = -2x + 6  

2x + 3y = 6 => answer in standard form

hope this helps :/

the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. hope this ! mark brainliest! you v much! : )

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)