One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. When the rods are exposed to near-infrared light from a laser, they heat up, killing the cell, while cells without rods are left unscathed (Wong et al., 2005). Suppose that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5. What is the probability that the cell will be killed

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ''.

This means that the cell will get killed if happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.

Here, P() = 0.2, P() = 0.4, P() = 0.3, P() = 0.6, P() = 0.5.

So, the probability that the cell will be killed is given by;

P(A)=

P(A) =

P(A) =

P(A) = 1 - 0.0672 = 0.9328

Hence, the probability that the cell will be killed is 0.9328.

idk

step-by-step explanation:

use that smart brain

the 4th choice is the correct one

step-by-step explanation: