The Pythagorean theorem states that the sum of the squares of the legs of a right triangle is equal to the square of the hypotenuse by the formula a2 + b2 = c2.
If a is a rational number and b is a rational number, why could c be an irrational number?
O The square of rational numbers is irrational, and sum of two irrational numbers is irrational.
O The product of two rational numbers is rational, and the sum of two rational numbers is irrational.
O The left side of the equation will result in a rational number, which is a perfect square.
O The left side of the equation will result in a rational number, which could be a non-perfect square.

d

because parallelagram have all 4 angels the same size dependeing and a rectangle and square are oth parallelogram

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

using pemdas, (order of operations) you'll see the answer is 24.