¿Cuál de los siguientes puntos no pertenece a la función cuadrática f(x) = 1-x^2 ?

Step-by-step explanation:

The question lacks the e=required option. Find the complete question below with options.

Which of the following points does not belong to the quadratic function

f(x) = 1-x²?

a.(0,1) b.(1,0) c.(-1,0)

Let f(x) = 0

The equation becomes 1-x² = 0

Solving 1-x² = 0 for x;

subtract 1 from both sides;

1-x²-1 = 0-1

-x² = -1

multiply both sides by minus sign

-(-x²) = -(-1)

x² = 1

take square root of both sides;

√x² = ±√1

x = ±1

x = 1 and x = -1

when x = 1

f(x) = y = 1-1²

y = 1-1

y = 0

when x = -1

f(x) = y = 1-(-1)²

y = 1-1

y = 0

Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions