M angle ABF=(7x+20)^ ,m angle FBC=[2x-5)^ and m angle ABC=159^ , find the value of x.

19 1/3°

Step-by-step explanation:

Given the expressions ABF=(7x+20)° m angle FBC=[2x-5)° and m angle ABC=159°

The addition properties is there fore true for the three angles;

<ABC = <ABF+<FBC

159 = 7x+20+2x-5

159 = 9x-15

Add 15 to both sides

159+15 = 9x-15+15

174 = 9x

9x = 174

Divide both sides by 9

9x/9 = 174/9

x = 19 1/3°

The value of x is 19 1/3°

.mp4 files, because, video

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg