The interval for which the quotient is continuous is the intersection of the above intervals. therefore, the quotient 12 x 12 x is continuous on the interval

The common continuous interval will be (0,∞).

Step-by-step explanation:

Given that,

The numerator = 12+√x

The denominator = √12+x

We know that,

For the numerator,

Any function under square root should be greater than and equal to the zero.

So, the continuous interval is (0, ∞)

For the denominator,

The interval for the continuous and non zero function is,

(-12, ∞)

We need to calculate the continuous interval

Using given quotient

The continuous interval of numerator and  denominator are (0, ∞) and (-12, ∞).

Hence, The common continuous interval will be (0,∞).

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.