the length of a rectangle is 3 inches more than it’s width. if the perimeter is 42 inches, find the dimensions of the rectangle

length = 12

width = 9

Step-by-step explanation:

We can use a system of linear equations to solve this problem. Lets make the variable L represent length and W represent width.

So we know that the length is 3 more than the width. An equation for this would be:

W = L - 3

We also know that the perimeter is 42 inches. The perimeter of a rectangle, using the variables L and W, is 2L + 2W, or 2(L + W). Using this, we can make the equation:

2(L + W) = 42

We can simplify the last equation by dividing both sides by 2:

L + W = 21

So now we have the two equations:

W = L - 3

L + W = 21

From here, there are multiple ways this question can be solved. I am going to use the substitution method here.

Knowing that W = L - 3, we can replace W in the second equation with L - 3.

L + L - 3 = 21

Add 3 to both sides.

2L = 24

Divide both sides by 2.

L = 12

Now we know that L = 12. Using this, we can replace L with 12 in the first equation to solve for W.

W = 12 - 3

W = 9

So:

L = length = 12

W = width = 9

I hope you find my answer helpful.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .