Determine the range and injective of the function.

j(x) = -x - 1

Answer and Step-by-step explanation:

Solution:

Range:

Let f(x) = -x-1

                        Here a=0 and b= -1, x=-b/a

Put the values, we get

       X= - (-1)/0 = infinity

Hence the range of the function f(x) = (-∞, ∞)

Injective:

A function is said to be injective if f(x1) = f(x2), gives x1=x2

Let f(x1) = -x1-1

 f(x2) = -x2-1

 f(x1) = f(x2)

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

i’m sorry but i don’t know sorry