Use the given endpoint Y and the midpoint M of YZ (there is a line over YZ) to find the coordinates of the other endpoint Z

The x-coordinate of our midpoint = 3

The x-coordinate of Y = 0

k  = x-coordinate of Z

3 = (0 + k) / 2

Multiply both sides by 2

6 = k + 0

Simplify

6 = k

The y-coordinate of our midpoint = 3

the y-coordinate of Y = 5

w = y-coordinate of Z

3 = (w + 5) / 2

Multiply both sides by 2

6 = w + 5

Subtract 5 from both sides

1 = w

For problem #17, Z(6, 1)

Let's do problem 18 now.

The x-coordinate of our midpoint = 5

The x-coordinate of Y = -1

k = x-coordinate of Z

5 = (k + (-1)) / 2

Multiply both sides by 2

10 = k + (-1)

Simplify the right side

10 = k - 1

Add 1 to both sides

11 = k

The y-coordinate of our midpoint = 9

The y-coordinate of Y = -3

w = y-coordinate of Z

9 = (w + (-3)) / 2

Multiply both sides by 2

18 = w + (-3)

Simplify the right side

18 = w - 3

Add 3 to both sides

21 = w

For problem #18, Z(11, 21)

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.