A Toyota Prius and a Dodge Circuit leave an intersection at the same time. The Prius heads east at an average speed of 50 miles per hour, while the Circuit heads south at an average speed of 45 miles and hour. After 30 minutes, the two cars are about miles apart. After 2 hours, the two cars are about miles apart. Write an express for the distance, d (in miles) after t hours.

33.634 ; 134.536 ; d = √[(50t)² + (45t)²]

Step-by-step explanation:

Given the following :

Toyota Prius = East at 50mph

Dodge Circuit = South at 45mph

Distance apart after 30 minutes :

Distance = speed * time

Distance moved by Prius = ( 50mph × 0.5hr) = 25 miles

Distance moved by Circuit = ( 45mph × 0.5hr) = 22.5 miles

Hence Displacement after 30 minutes :

d = √(25² + 22.5²)

d = √625 + 506.25

d = √1131.25

d = 33.634 miles

Distance apart after 2 hours :

Distance = speed * time

Distance moved by Prius = ( 50mph × 2hr) = 100 miles

Distance moved by Circuit = ( 45mph × 2hr) = 90 miles

Hence Displacement after 2 hours :

d = √(100² + 90²)

d = √10000 + 8100

d = √18100

d = 134.536 miles

Distance d in miles after t hours :

d = √[(50t)² + (45t)²]

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.