Find the least common multiple of 45 and 120

Step-by-step explanation:

Steps for finding L.C.M of the given numbers :

First of all find the prime factors of each numbers.

Take out the common prime factors.

Also take out the remaining prime factors.

Multiply those all prime factors and obtain L.C.M. If there is not any common prime factors then their L.C.M is the product of the given numbers.

Now,let's find the least common multiple ( L.C.M ) of 45 and 120 following those steps :

prime factors of 45 = 3 × 3 × 5

prime factors of 120 = 2 × 2 × 2 × 3 × 5

Common prime factors= 3 and 5

Remaining prime factors = 2 , 2 , 2 and 3

Multiply all the prime factors to obtain L.C.M

Hope I helped!

Best regards! :D

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

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step-by-step explanation: