A water tank holds 486 gallons but leaking at a rate 4 gallons per week. A second water tank holds 648 gallons but is leaking at a rate of 7 gallons per week. After how many weeks will the amount of water in the 2 tanks? The amount of water that holds the two tanks will be the same in _ weeks.

The first tank contains

486 gal - (4 gal/week) t

gal of water after t weeks.

Similarly, the second tank contains

648 gal - (7 gal/week) t

gal of water.

The tanks hold the same amount of water when these two amounts are equal:

486 gal - (4 gal/week) t = 648 gal - (7 gal/week) t

(7 gal/week) t - (4 gal/week) t = 648 gal - 486 gal

(3 gal/week) t = 162 gal

t = (162 gal) / (3 gal/week)

t = 54 weeks

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step-by-step explanation:

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions