For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 12 N acts on a certain object, the acceleration of the object is 3 m/s?. If the force is changed to 40 N, what will be the acceleration of the object?

answer: sine

step-by-step explanation:

36

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.