The frequency table shows the results of tossing a number cube 50 times. Which statement is reasonable, based on the data?

Option (1) is the correct option.

Step-by-step explanation:

From the given frequency table,

Option (1).

Tossing an even number is more likely than tossing an odd number.

Frequencies of tossing even numbers 2, 4, 6 = 10, 10, 9

Frequencies of tossing odd numbers 1, 3, 5 = 8, 6, 7

Which shows frequencies of tossing even numbers are more.

Therefore, Option (1) is correct.

Option (2)

The number 2 will be the next number tossed.

Since it is unpredictable, therefore, this option is incorrect.

Option (3)

Number 4 is half as likely to be tossed as the number 3.

Frequency of tossing number 3 = 6

Frequency of tossing 4 = 10

Frequency of tossing 3 is not the half of tossing 4.

Therefore, Option (3) is incorrect.

Option (4)

Probability of tossing the number 2 =

                                                           =

                                                           =

                                                           =

Therefore, option (4) is incorrect.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

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