Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can run at 6 mph and walk 4 mph, how long will he be from home?

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time () that Keenan will be from home is the sum of run (), hang out () and walk times (), measured in hours:

If Keenan runs and walks at constant speed, then equation above can be expanded:

Where:

, - Run and walk distances, measured in miles.

, - Run and walk speeds, measured in miles per hour.

Given that , , and , the total time is:

()

Kennan will be from home approximately an hour and 48 minutes.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!