Mathematics, 11.11.2019 16:31 sarahsteelman
Let f(x) = (2x+1)^3 and let g be the inverse function of f. given that f(0)=1, what is the value of g'(1)?
Answers: 2
![2 x + 1 = \sqrt[3]{y} \\ 2 x = \sqrt[3]{y}- 1 \\ x = \frac{ \sqrt[3]{y}-1}{2} \\ f^{-1}(x)= \frac{ \sqrt[3]{x}-1 }{2} = g ( x )](/tpl/images/0369/1257/bbeaf.png)
![\frac{1}{6 \sqrt[3]{ x^{2} } }](/tpl/images/0369/1257/9ce73.png)
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Let f(x) = (2x+1)^3 and let g be the inverse function of f. given that f(0)=1, what is the value of...
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