The distribution of monthly rent for one-bedroom apartments in a city is approximately normal with mean $936 and standard deviation $61. A graduate student is looking for a one-bedroom apartment and wants to pay no more than $800 in monthly rent. Of the following, which is the best estimate of the percent of one-bedroom apartments in the city with a monthly rent of at most $800 ? (A) 1.3%
(B) 2.5%
(C) 50%
(D) 95%
(E) 97.5%

1.3% of one-bedroom apartments in the city have a monthly rent of at most $800

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

Given that mean (μ) = $936 and standard deviation(σ) = $61.

Let x represent the monthly rent, hence:

The percentage of apartments with a monthly rent at most $800 is:

x < $800

From the normal distribution table, P(x < 800) = P(z < -2.23) = 0.0129 = 1.4%

Therefore 1.3% of one-bedroom apartments in the city have a monthly rent of at most $800

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(A) 1.3%

Step-by-step explanation:

Given: The monthly rent for one-bedroom apartments in a city is approximately normal with mean $936 and standard deviation $61.

i.e.

Let X denotes the monthly rent for one-bedroom apartments.

Required probability =

Hence, the correct option is (A) 1.3%

answer: 2/4

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.