The table shows the test scores of students who studied for a test as a group (Group A) and students who studied individually (Group B). Which would be the best measures of center and variation to use to compare the data? Student Test Scores (out of 100) 80 Group A Group B 84 92 77 85 92 86 96 87 88 88 85 84 76 83 92 80 100 88 The scores of Group B are skewed right, so the mean and range are the best measures for comparison Both distributions are nearly symmetric, so the mean and the standard deviation are the best measures for comparison O Both distributions are nearly symmetric, so the median and the interquartile range are the best measures for comparison. O The scores of both groups are skewed, so the median and standard deviation are the best measures for comparison

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the answer to that one is b