Mathematics, 20.09.2020 20:01 claytonp7695
The perimeter of a rectangle is found by multiplying the sum of the length, shown as I,
and the width, shown as w, by 2. The length of a certain rectangle is 20. Which
inequality shows that the perimeter of this rectangle is less than 57 units?
A.2 (20+w) > 57
B.2 (20 + w) < 57
C.2 (20) (w) > 57
D.2 (20) (w) < 57
Answers: 2
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The perimeter of a rectangle is found by multiplying the sum of the length, shown as I,
and the wid...
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