If the sides of a triangle are produced in order prove that the sum ofexterior angles so formed is equal to four right angles

Step-by-step explanation:

Let a, b, c be the measures of the interior angles and x, y, z be the measures of the exterior angles of the triangle. Where x and adjacent to a, y is adjacent to b and z is adjacent to c.

By interior angle sum postulate of a triangle:

a + b + c = 180°... (1)

Therefore, by remote interior angle theorem:

x = b + c.... (2)

y = a + c..... (3)

z = a + b.... (4)

Adding equations (2), (3) & (4)

x + y + z = b + c + a + c + a + b

x + y + z = 2a + 2b + 2c

x + y + z = 2(a + b + c)... (5)

From equations (1) & (5)

Thus, the sum of exterior angles so formed is equal to four right angles.

Proved.

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step-by-step explanation:

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m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°