Traffic along a stretch of road moves at an average speed that varies inversely with the number of cars on it. When there are 1500 cars, the average speed is 45 mi/h. What is the average speed when there are 1800 cars?

37.5 miles per hour

Step-by-step explanation:

The traffic along a stretch road moves at an average speed that carried inversely as the number of cars

Average speed= k/number of cars.

When there are 1,500 cars the average speed is 45

The first step is to calculate the constant k

45= k/1500

k = 1,500 × 45

k= 67,500

Therefore the average speed when there are 1,800 cars can be calculated as follows

Average speed= 67,500/1,800

= 37.5 miles per hour

Hence the average speed is 37.5 moles per hour

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

yes. we do proportions in probabilities.