A group entered the musem at 3:30 and came out at 5:15 how lomh were they inside the museum

The group spent 1 hour and 45 minutes inside the Museum

Step-by-step explanation:

Here, given the time in which a group of people entered into a company and that time they got out, we want to know the number of minutes they spent inside the museum

Mathematically that would be;

5:15 - 3:30

3:30 - 4:30 is an hour, 4:30 to 5:30 is another one hour making 2, but only 15 minutes was spent before 5:30

So the time spent will be 2 hours - 15 minutes p 1 hour 45 minutes

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: