What are the three integers all less than 25 whose range is 10 and mean is 13

Let  x be the first integer , y be the second integer , and z be the third integer

x < y < z < 25

We know that

Median=13

Median=(x+y+z)/3

13=(x+y+z)/3

x+y+z=39> equation 1

Range=10

The range is the difference between the largest number within the set and the smallest number in the set

So  range=z-x

z-x=10> z=x+10> equation 2

to find the solution we will assume different values of x (See the attached table)    

terms

x < y < z < 25

z=x+10

y=39-z-x

The solution can be

7,15,17

8,13,18

9,11,19    

hope it helps!

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

i think the amount would be $140.62