Lets say scores on an emotional intelligence test are normally distributed with a mean equal to 110.7 and a standard deviation equal to 24.5. The question asks: Above which value fall 50 percent of scores. PLEASE SHOW STEP BY STEP !!!

The percentage of fall 50 percent of scores is 0.68

Step-by-step explanation:

Explanation:-

Given mean of the population = 110.7

standard deviation of the Population = 24.5

Let 'X' be the random variable in normal distribution

Given X = 50

   Now  

The probability that fall 50 percent of scores.

P( X < 50) = P( Z < -2.477)

                = 1- P(Z>2.477)

               = 1 - (0.5 + A(2.477)

              = 0.5 - A(2.477)

             = 0.5 - 0.4932

            = 0.0068  

The percentage of fall 50 percent of scores is 0.68

answer: i think it's a

step-by-step explanation:

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540