Given:
Seven times the smaller of two consecutive even integers is the same as -300 minus 4 times the larger integer.
To find:
The integers
.
Solution:
Let the smaller even integer be x.
So, larger even integer is x+2 because they are consecutive even integers.
Seven times the smaller integer = 7x
-300 minus 4 times the larger integer = -300-4(x+2)
Now,
![7x=-300-4(x+2)](/tpl/images/0775/9463/d0f0b.png)
![7x=-300-4x-8](/tpl/images/0775/9463/0b64b.png)
![7x+4x=-308](/tpl/images/0775/9463/632a4.png)
![11x=-308](/tpl/images/0775/9463/55cf8.png)
Divide both sides by 11.
![x=\dfrac{-308}{11}](/tpl/images/0775/9463/161f2.png)
![x=-28](/tpl/images/0775/9463/67f5e.png)
So, the smaller even integer is -28.
![x+2=-28+2=-26](/tpl/images/0775/9463/b5851.png)
So, the larger even integer is -26.