You were wrong the answer was -6, -2,2,6

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Rachel is studying the population of a particular bird species in a national park. she observes every 10th bird of that species that she can find in the park. her conclusion is that the birds living in the park who belong to that species generally feed on insects. rachel's sample is . based on the sample she picked, rachel's generalization is . reset next

The host of a game show is holding a bag with chips to see what prizes the contestants will play for. five (5) of the chips say “new car” ten (10) of the chips say “new tv” three (3) of the chips say “trip to france” contestant named “patty” reaches into the bag. a. what is the probability of choosing a tv chip? b. what is the probability of choosing a car chip next without replacing the 1st chip? c. are these dependent or independent events?