What is the solution set of the quadratic equation 3x^2 - 2x - 1 = x^2 - 6x +3

x = -1 ± √3

Step-by-step explanation:

3x² − 2x − 1 = x² − 6x + 3

Move everything to one side.

2x² + 4x − 4 = 0

Divide by 2.

x² + 2x − 2 = 0

Solve with quadratic formula, or by completing the square.

x² + 2x = 2

x² + 2x + 1 = 3

(x + 1)² = 3

x + 1 = ±√3

x = -1 ± √3

take it another

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64