Write an equation of the parabola in vertex form.

f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. ... When written in "vertex form": • (h, k) is the vertex of the parabola, and x = h is the axis of symmetry.

y =0.25(x-4 )^{2}-1

Step-by-step explanation:

The formula of vertex form is as follows:

Y = a(x-h)^2+k

h = the x value for the vertex (in this case it is 4)

k = the y value for the vertex (in this case it is -1)

If you input these into the equation you are left with:

Y = a(x-4)^2-1

To find 'a' I just entered this equation into the Desmos calculator and messed around with the value until the y-intercept was (8,3)

I hope this was able to help! ^_^

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.