Implement bi-section method and Newton method for the solution/root finding of the following two functions. Please output the final root approximation and the total number of iterations involved. Here we choose the function value absolute error as error tolerance in the scale of 5 10− ε = . Submit your matlab codes (*.m) with other parts of the home work. (TA will run your code successfully to receive full credit) For Newton method, we can simply take the left end of the given interval as the initial guess. 1. f(x) = e^x + 2^-x + 2cos(x) − 6, p∈[1,2]
2. f(x) = (x - 2)2 - ln(x), p[e,4]

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation:

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

the answer is su.k.my? ? co.kc