What are the coordinates of the
3/4
point of the way from A(-6, -3)
to B(10,9)?

The coordinates of the point are (6, 6).

Step-by-step explanation:

Find the difference in x-coordinates.

10 - (-6) = 16

Find 3/4 of the difference in x

3/4 * 16 = 3/4 * 16/1 = 48/4 = 12

Add 12 to the x-coordinate of point A.

-6 + 12 = 6

The x-coordinate is 6.

Now we do the same for the y-coordinates.

Find the difference in y-coordinates.

9 - (-3) = 12

Find 3/4 of the difference in y

3/4 * 12 = 3/4 * 12/1 = 36/4 = 9

Add 9 to the y-coordinate of point A.

-3 + 9 = 6

The y-coordinate is 6.

The coordinates of the point are (6, 6).

the answer is simply just 6n add the two together as they have an n

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.