Two objects are moving along separate linear paths were each path is described by position D & thyme tea the variable de is measured in meters and the variable T is measured in seconds the equation describing the graph of the position of the first object with respect to time is D equals 2.5 T +2 point to the graph of the position of the second object is pear is a parallel path line passing through T equals0 d equals one what is the equation of the second graph

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

the correct answer is b.

this is because an open circle means < or > & since the line goes left it is < -3.

the next one has a filled circle so it can only be ≥ or ≤ and since the line goes right from 1 it is ≥ 1

hope that