Suppose it is known that 10 percent of a certain population has an eye disease. If a random sample of 25 people is drawn from this population, use the binomial table find the
probability that five or fewer will have that eye disease. That probability according to the
binomial table is
0.9020
0.9905
0.9666
0.7636
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you just switch the numbers basically so it would be 3/17

i think it is c hope that

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft

2*2=3

two times two is four

i dont understand what you mean so pls comment