Write an equation in slope-intercept form of the line that is a segment bisector of both AB and CD.

y = -5x + 7

Step-by-step explanation:

Segment bisector of the segments AB and CD will pass through the midpoint of these segments.

Midpoint of a segment is given by the coordinates =

where, and are the coordinates of the extreme ends of the segments.

Coordinates of the midpoint of AB =

                                                          = (1, 2)

Coordinates of the midpoint of CD =

                                                          = (2, -3)

Let the equation of the line will be,

Slope of the line passing through two points and is,

m =

   =

   = -5

Therefore, equation of the line will be passing through (1, 2) and slope (-5),

y - 2 = (-5)(x - 1)

y = -5x + 5 + 2

y = -5x + 7

25.2

step-by-step explanation:

2+4x6-8/10= 25.2

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐