The perimeter of a rectangle is 700 yards. What are the dimensions of the rectangle if the length is 50 yards more than the width?

width = 150 yards

length = 200 yards

Step-by-step explanation:

Using the information given to us, we can make the following two equations:

2L + 2W = 700

L = W + 50

where L is the length in yards and W is the width in yards. This could treat these two equations as a system of linear equations. There are multiple ways to solve a system of linear equations, but I am going to solve this by substitution. Before doing that, I am first going to simplify the first equation, as it will make solving the system easier.

2L + 2W = 700

Divide both sides by 2.

L + W = 350

Since L = W + 50, we can substitute W + 50 for L in the equation L + W = 700.

(W + 50) + W = 350

2W + 50 = 350

2W = 300

W = 150

Now that we found what W is, we can solve for L by plugging 150 into either one of the equations. I am going to plug it into the equation L = W + 50.

L = 150 + 50

L = 200

Now we found what L is. So now we know that the width is 150 yards and the length is 200 yards.

I hope you find my answer and explanation helpful. Happy studying. :)

answer: 2/4

step-by-step explanation:

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)