Write the equation of a line that passes through the point (-8,2) and is parallel to the line 3x-2y=12

The equation of a line that passes through the point (-8,2) and is parallel to the line 3x-2y=12 is 2y - 3x = 28

The equation of a line in point-slope form is expressed as;

m is the slope of the line

(x1, y1) is the point on the line = (-8, 2)

Given the line 3x - 2y =12

-2y = -3x + 12

y = 3/2 x - 6

The slope of the line is 3/2

Get the required equation:

Hence the equation of a line that passes through the point (-8,2) and is parallel to the line 3x-2y=12 is 2y - 3x = 28

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Step-by-step explanation:

-2y = -3x + 12

2y = 3x - 12

y = 3/2x - 6

y - 2 = 3/2(x + 8)

y - 2 = 3/2x + 12

y = 3/2x + 14

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.