Find the interquartile range (IQR) of the data in the dot plot below. players
Players at each table
in Bev's bingo hall

The interquartile range (IQR), which is the difference of Q3 and Q1 is: 3.5

Recall:

To find the interquartile range (IQR) of the data given in the dot plot, take the following steps:

Step 1: List all the data given in the dot plot (each dot represents a data plot)

The data points are: 0, 1, 1, 3, 3, 3, 4, 5, 7

Step 2: Find the First Quartile (the middle value of the first half of the data points).

0, (1, 1,) 3, 3, 3, 4, 5, 7

The average of 1 and 1 = the middle of the first half

Step 3: Find the Third Quartile (the middle value of the second half of the data points).

0, 1, 1, 3, 3, 3, (4, 5,) 7

The average of 1 and 1 = the middle of the second half

Step 4: Find the Interquartile Range (IQR).

IQR = 4.5 - 1

IQR = 3.5

Therefore, the interquartile range (IQR), which is the difference of Q3 and Q1 is: 3.5

Learn more here:

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Put the numbers in order from least to greatest and find the median. 0,1,1,3,3,3,4,5,7. 3 is the median, so find quartile 1 and quartile 3.

Q1 is 1, and q3 is 5. To find the quartiles, find the median of the lower halves(leave the median we just found out of it.) You get 1 for the first half and 5 for the other.

45 degres

step-by-step explanation:

sorey if i hav bad engelish im bad engelish

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0