A tourist in France wants to visit 10 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order?

1/3628800

Step-by-step explanation:

This question requires that we calculate

1/number of permutations of 10 cities

= P(n,k) = n!/(n-k)!

We have

n = 10

k = 10

= 10!/(10-10)!

= 10!

number of permutations of 10 cities 10! This Is equal to 3,628,800

From this answer we the probability of doing a random tour of these 10 different cities in alphabetical order.

And this is

= 1/3,628,800

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

rx and sx

step-by-step explanation: