John invests $3,000 into an account that earns 4.7% interest compounded quarterly. Write an equation and us it to find the value of John's investment after 12 years

The equation is;

A = 9,000(1 + 0.047/4)^48

The value is

$15,767.28

Step-by-step explanation:

Here we want to find the value of an investment after 12 years, given its interest rate;

Mathematically the amount which is the value would be;

A = I( 1 + r/n)^nt

Where A is the amount in 12 years

I is the initial amount invested = $3,000

r is the interest rate = 4.7% = 4.7/100 = 0.047

n is the number of times interest is compounded yearly = 4 since it is quarterly ( once every three months)

t is the number of years = 12

Substituting these values, we have

A = 9,000(1 + 0.047/4)^(12^4)

A = 9,000(1 + 0.047/4)^48

The above is the expression

A = 9,000(1 + 0.01175)^48

A = 9,000(1.01175)^48

A = $15,767.28

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3