write the equation of the parabola and a vertex form and standard form given the following information

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

(9)

Here (h, k) = (3, - 2), thus

y = a(x - 3)² - 2

To find a substitute (2, 3) into the equation

3 = a(2 - 3)² - 2 ( add 2 to both sides )

5 = a(- 1)² = a , then

y = 5(x - 3)² - 2 ← in vertex form

y = 5(x² - 6x + 9) - 2

   = 5x² - 30x + 45 - 2

y = 5x² - 30x + 43 ← in standard form

(10)

Here (h, k) = (2, - 5), thus

y = a(x - 2)² - 5

To find a substitute (5, 4) into the equation

4 = a(5 - 2)² - 5 ( add 5 to both sides )

9 = a(- 3)² = 9a ( divide both sides by 9 )

a = 1

y = (x - 2)² - 5 ← in vertex form

y = x² - 4x + 4 - 5

y = x² - 4x - 1 ← in standard form

 9) y = 5(x - 3)² - 2         y = 5x² - 30x + 43

              10) y = (x - 2)² - 5           y =  x² - 4x + 2

Step-by-step explanation:

The Vertex form of a quadratic equation is:    y = a(x - h)² + k     where

The Standard form of a quadratic equation is: y = ax² + bx + c

--> this is found by expanding the vertex form and adding like terms.

Input Vertex (h, k) and Point (x, y) into the Vertex form to solve for "a"

9) Vertex (h, k) = (3, -2) and Point (x, y) = (2, 3)

   3 = a(2 - 3)² - 2

  3 = a(-1)² - 2

  5 = a(1)

  5 = a

Vertex form: y = 5(x - 3)² - 2

Standard Form: y = 5(x² - 6x + 9) - 2

                          y = 5x² - 30x + 45 - 2

                          y = 5x² - 30x + 43

10) Vertex (h, k) = (2, -5) and Point (x, y) = (5, 4)

  4 = a(5 - 2)² - 5

  4 = a(3)² - 5

  9 = a(9)

  1 = a

Vertex form: y = (x - 2)² - 5

Standard Form: y = (x² - 4x + 4) - 2

                          y =  x² - 4x + 2

answer: what

step-by-step explanation:

option 1

data plot with   3 dots over 33, 1 dot over 34, 2 dots over 35, no dot over 36, 1 dot over 37, 2 dots over 38, 4 dots over 39, and 2 dot over 40.