3(m - 1) = 5m +3 -2m please help me solve this step by step asap!

0 = 6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(m−1)=5m+3−2m

(3)(m)+(3)(−1)=5m+3+−2m (Distribute)

3m+−3=5m+3+−2m

3m−3=(5m+−2m)+(3) (Combine Like Terms)

3m−3=3m+3

3m−3=3m+3

Step 2: Subtract 3m from both sides.

3m−3−3m=3m+3−3m

−3=3

Step 3: Add 3 to both sides.

−3+3=3+3

0=6

answer: 34rtyj,jkhtyetwrhyjeuiejnbhdfknbkguxfrbhkfdbjvkmbd,kvbsd.kxjvbhjnfbgjxdfn

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v