The sum of two numbers is 83. The sum of 2 times the first number and 3 times the second number is 203. Write a system of equations and use the system to find the two numbers.
The two numbers are
and

the two numbers are 46 and 37

Step-by-step explanation:

Given that:

Sum of two numbers = 83

Sum of two times the first number and three times the second number = 203

From the question :

Let the numbers = a and b respectively

a + b = 83 - - - (1)

2*a + 3*b = 203

2a + 3b = 203 - - - (2)

From (1) :

a + b = 83

a = 83 - b

Substitute a = 83 - b into (2)

2(83 - b) + 3b = 203

166 - 2b + 3b = 203

166 + b = 203

b = 203 - 166

b = 37

From;

a + b = 83

a = 83 - b

a = 83 - 37

a = 46

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral