Caleb and Mike both score the same amount of points in a game. Caleb has fifteen less than the total number of points. Mike has twice the total number of points decreased 201. how many points do they have altogether?

129 points
Step-by-step explanation:
Let L and C represent the scores of Luke and Caleb, respectively.
L = 2C -15 . . . . . Luke scored 15 less than twice the number Caleb did
L +C = 201 . . . . . they scored 201 points altogether
Add twice the second equation to the first:
2(L +C) + (L) = 2(201) + (2C -15)
3L +2C = 387 +2C . . . . simplify
3L = 387 . . . . . . . . . . . . .subtract 2C
L = 387/3 = 129 . . . . . . .divide by 3
Luke scored 129 points.

Ummm ok. for informing us

B.-2,3 because it is touch the -3 i think that the answer