The formula to calculate the gravitational force between two objects is F_g=\frac{GM_1M_2}{r^2},F g

=
r
2

GM
1

M
2



, where M_1M
1

and M_2M
2

are the masses of the objects, GG is the gravitational constant and rr is the distance between the objects. Solve for M_1M
1

in terms of F_g, F
g

, G, G, M_2M
2

and r. r.

step-by-step explanation:

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for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

x=6 and x=3

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