You wish to dilute some chemical with a diluting agent. You have 50mL of chemical and the ratio must be 1:60 (chemical : agent). The diluting agent is kept in three sizes 1Litre, 5 Litres and 10 Litres. You have to carry it to the mixing station, which is 300 meters away, so you want to carry the smallest size that will do the job.
which container would you take? (show rough workings).

i am sure it will be 90 degrees.

step-by-step explanation:

50

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

6/20

step-by-step explanation: