Two points A and B are on opposite sides of a building. A surveyor selects a third point C to place a transit. Point C is 52 feet from point A and 64 feet from point B. The angle ACB is 52°. How far apart are points A and B? Round to the 10th place.

Step-by-step explanation:1.

Use law of cosine.

AB^2 = AC^2 + BC^2 - 2 * AC * BC * cos(angle ACB)

AB^2 = 53^2 + 71^2 - 2(53)(71)cos(53)

Using calculator,

AB = about 57.6259 feet

2.

Law of cosine again.

d^2 = 400^2 + 90^2 - 2(400)(90)cos(45)

using calculator,

d = about 342.3278 feet

77

step-by-step explanation:

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