Step-by-step explanation:
4x β y = β11
2x + 3y = 5
lets multiply the second equation by -2 and add it to the first:
4x β y = β11
-4x - 6y = -10
0 Β - 7y = -21
y = -21/-7
y = 3
now we substitute this result in the first equation to find x:
4x β y = β11
4x - 3 = -11
4x = -8
x = -8/4
x = 2
so the solution is y = 3 and x =2
4x β 9y = β21
β10y = β30
we solve for y
β10y = β30
y = -30/-10
y = 3
and substitute in the first equation:
4x β 9y = β21
4x β 9(3) = β21
4x - 27 = -21
4x = 6
x = 6/4 = 3/2
so the solution is x = 3/2 and y = 3
4x + 3y = 5
2y = β6
we solve for y:
2y = β6
y = -6/2
y = -3
we do substitute in the first equation:
4x + 3y = 5
4x + 3(-3) = 5
4x - 9 = 5
4x = 14
x = 14/4
x = 7/2
so the solution is x = 7/2 and y = -3
7x β 3y = β11
9x = β6
we solve for x:
9x = β6
x = -6/9
x = -2/3
then we substitute in the first equation the result found:
7x β 3y = β11
7(-2/3) β 3y = β11
-14/3 - 3y = -11
we multiply by 3 to eliminate fractions:
-14 - 9y = -33
9y = 19
y = 19/9
so the solution is x = -2/3 and y = 19/9
12x β 3y = β33
14x = β28
we solve for x:
14x = β28
x = -28/14
x = -2
then we substitute in the first equation:
12x β 3y = β33
12(-2) β 3y = β33
-24 - 3y = -33
3y = 9
y = 3
then the solution is x = -2 and y = 3