Find L on A (-2,0) and B(4,3) that is 2/3 of the distance from A to B. A. (0,1)

B (1,3/2)

C(2/3, 3/2)

D(2,2)

Greetings from Brasil...

First we will calculate the distance between points A and B....

The expression that allows you to calculate the distance between two points is:

d(A; B) = √[(4 - (- 2))² + (3 - 0)²]

d(A; B) = √[6² + 3²]

45 = 3² · 5

d(A; B) = 3√5

L is 2/3 of the distance from AB, so

L = 2/3 · d(A; B)

L = 2/3 · 3√5

For the coordinates of point L: let us use similarity of triangles...

BM/LN = AB/AL     - refer to attached

3/Yl = 3√5/2√5

Yl = 2

As we can see in the graph, when Y = 2, X is also 2, so

there are other ways to accomplish this task

power property.

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step-by-step explanation: